35x^2-44+12=0

Solution for 35x^2-44+12=0 equation:

35x^2-44+12=0

We add all the numbers together, and all the variables

35x^2-32=0

a = 35; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·35·(-32)
Δ = 4480
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4480}=\sqrt{64*70}=\sqrt{64}*\sqrt{70}=8\sqrt{70}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{70}}{2*35}=\frac{0-8\sqrt{70}}{70}
=-\frac{8\sqrt{70}}{70}
=-\frac{4\sqrt{70}}{35}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{70}}{2*35}=\frac{0+8\sqrt{70}}{70}
=\frac{8\sqrt{70}}{70}
=\frac{4\sqrt{70}}{35}
$